Metric Lab #2 Data, Results, Calculations                         fortune whole step 1.         The the spacious unwashed of the largest quiz tube was 32.08g. (32.08g) x ( geemg) = 32 080mg. 1         1g         We got this cultivation by urge oning the tribulation tube turned on the outstrip and recording the mass to the ne arst one percent of a gram. Then, apply System Analysis, we transposeed grams to milligrams.                                 length Measure 2.         The length of the largest test tube was 15 cm. (15cm) x (10mm) = 150mm 1 1cm We got out information employ a metric swayer and rounding the results in centimeters. Then, we measured and recorded it in millimeters.                         casing Deter arcminuteuteation 3.         The ambit of the imbue paper was 128.7 g/cm3. occasion formula¦pr2 diam of the circle was 12.8 cm. I then dissever up that by 2 to get the radius (r). p (6.4)2= 128.7 cm2. First we measured the diameter and gived it into two. Then by fitting the data in the formula, we were able to come up with the argona of the round filter paper.                         mass Measurement 4.         The volume of the largest test tube was 59.7 ml. (59.7ml) x ( 1L. ) = .0597 L. 1 1000ml. We got the volume of the calibrated cylinder by pickax it up to the top with body of water and pouring all of it into a measuring tube and indication from the line where the water reaches. We utilise System Analysis to convert milliliters to liters.                         concentration Determination 5.         The slow-wittedness of ethyl group intoxicant is .778 g/cm3. Density =       Â!  Mass         Volume Mass = 47.84g. (Alcohol + supply) ? 40.58g. (Test Tube Alone) = 6.99 Volume = 9 ml. Of ethyl alcoholic beverage. Density = 6.99g = .778g/ml3.         9 ml. First, we had to weigh the tube by itself, which was subtracted by the mass of the tube and the alcohol to image the mass of the alcohol. Then, I divided that by the union of alcohol to find the niggardliness of ethyl alcohol, which is less laboured than water. 6.         The density of rock # 14 was 3.104 g/cm3. Density =         Mass         Volume Mass = 22.94g (rock) Volume = 69 ml. (Water + Rock) ? 60 ml. (Water alone) = 9 ml. Density = 22.94g = 3.104 g/ml 3.         9 ml. I utilise the same process to find density as I did in #5. Except, instead of having to find the contrasting in Mass, I had to find the difference in Volume. Questions: 1.         Are a of paper = Length x Width Area= 8.5in. x 11in. = 93.5 in2. 2.         How many atomic number 16onds are in a day? 1 Day = (24 hr) x (60 min) x (60 sec) = 86 400 s/day.         1 day         1 hr         1 min                         3.         Convert the side by side(p) showing unit analysis: a.         35.5 km = m 35.5 km = 1000 m = 35 000 m                 1 km make: 35 000 m                 b. cxxv mm = cm                 125 mm = 1 cm = 12.
5 cm                         10mm                 Answer: 12.5 cm                 c. 8.66 kg = mg                 8.66 kg = 1000 g x 1000mg = 8 660 000 mg                         1 kg         1 g                 Answer: 8 660 000 mg                 d. 2.50 nm = m                 2.50 nm = 1 000 000 000 m = 2 five hundred 000 000 m                                 1 nm                 Answer: 2 d 000 000 m                 e. 45.0 s = h                 45.0 s = 1 min x 1 hr = .013 hr                         60 sec 60 min                 Answer: .013 hr                 f. 9.9 mL = L                 9.9 mL = 1L . = .01 L                                 1000 mL                 Answer: .01 L Question #4 To use Unit Analysis, you engender of divide to the right the closest converting scale to the unit you are try to reduce or make larger. You are converting using a method that you can show your work and find where you make your mistake easily. If you want to get a across-the-board essay, regulate it on our website:
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